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JEE Mains · Maths · STD 12 - 9. differential equations

ધારોકે \(y=y(x)\) એ વિકલ સમીકરણ \(x^3 d y+(x y-1) d x=0, x > 0, y\left(\frac{1}{2}\right)=3\) - નો ઉકેલ છે. તો \(y(1)=.........\)

  1. A \(1\)
  2. B \(e\)
  3. C \(2- e\)
  4. D \(3\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(1\)

Step-by-step Solution

Detailed explanation

\(\frac{d y}{d x}=\frac{1-x y}{x^3}=\frac{1}{x^3}-\frac{y}{x^2}\) \(\frac{d y}{d x}+\frac{y}{x^2}=\frac{1}{x^3}\) \(\text { If }=e^{\int \frac{1}{x^2} d x}=e^{-\frac{1}{x}}\)…
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