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JEE Mains · Maths · STD 12 - 1. relation and function

ધારોકે \(R\) પર વ્યાખ્યાયિત વાસ્તવિક મૂલ્ય વિધેયો \(f, g\) અને \(h\) એ \(f(x)=\left\{\begin{array}{cc}\frac{x}{|x|}, & x \neq 0 \\ 1, & x=0\end{array}, g(x)=\left\{\begin{array}{cc}\frac{\sin (x+1)}{(x+1)}, & x \neq-1 \\ 1, & x=-1\end{array}\right.\right.\) અને \(h(x)=2[x]-f(x)\), જ્યાં \([x]\) એ મહતમ પૂર્ણાંક \(\leq x\) પ્રમાણે છે.તો \(\lim _{x \rightarrow 1} g(h(x-1))=...........\)

  1. A \(1\)
  2. B \(-1\)
  3. C \(-1\)
  4. D \(0\)
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Answer & Solution

Correct Answer

(A) \(1\)

Step-by-step Solution

Detailed explanation

\(LHL =\lim _{ k \rightarrow 0} g ( h (- k )) , k > 0\) \(=\lim _{ k \rightarrow 0} g (-2+1) \because f ( x )=-1 \forall x < 0\) \(= g (-1)=1\) \(RHL =\lim _{ k \rightarrow 0} g ( h ( k )) , k > 0\) \(=\lim _{ k \rightarrow 0} g (-1) , \because f ( x )=1, \forall x > 0\) \(=1\)
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