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JEE Mains · Maths · STD 12 - 6. Application of derivatives

ધારો કે \(f\left( x \right)\) એ \( x=1 \) અને \( x=2\)  આગળ આત્યંતિક મૂલ્યો ધરાવતી ચાર ઘાતવાળી બહુપદી છે. જો \(\mathop {\lim }\limits_{x \to 0} \left[ {1 + \frac{{f\left( x \right)}}{{{x^2}}}} \right] = 3\),તો \(f\left( 2 \right)\) મેળવો.

  1. A \(4\)
  2. B \(-8\)
  3. C \(-4\)
  4. D \(0\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(0\)

Step-by-step Solution

Detailed explanation

\(\mathop {\lim }\limits_{x \to 0} \left( {\frac{{{x^2} + f\left( x \right)}}{{{x^2}}}} \right) = 3\), since, limit exits hence \({x^2} + f\left( x \right) = a{x^4} + b{x^3} + 3{x^2}\) \( \Rightarrow f\left( x \right) = a{x^4} + b{x^3} + 2{x^2}\)…
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