JEE Mains · Maths · STD 12 - 1. relation and function
Let \(f, g\) and \(h\) be the real valued functions defined on \(R\) as \(f(x)=\left\{\begin{array}{cc}\frac{x}{|x|}, & x \neq 0 \\ 1, & x=0\end{array}\right.\), \(g(x)=\left\{\begin{array}{cl}\frac{\sin (x+1)}{(x+1)}, & x \neq-1 \\1, & x=-1\end{array} \text { and } h(x)=2[x]-f(x),\right.\) where \([x]\) is the greatest integer \(\leq x\). Then the value of \(\lim _{x \rightarrow 1} g(h(x-1))\) is
- A \(1\)
- B \(-1\)
- C \(-1\)
- D \(0\)
Answer & Solution
Correct Answer
(A) \(1\)
Step-by-step Solution
Detailed explanation
\(LHL =\lim _{ k \rightarrow 0} g ( h (- k )) , k > 0\) \(=\lim _{ k \rightarrow 0} g (-2+1) \because f ( x )=-1 \forall x < 0\) \(= g (-1)=1\) \(RHL =\lim _{ k \rightarrow 0} g ( h ( k )) , k > 0\) \(=\lim _{ k \rightarrow 0} g (-1) , \because f ( x )=1, \forall x > 0\) \(=1\)
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