ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Maths · STD 12 - 5. continuity and differentiation

ધારોકે \(a \in Z\) અને \([t]\) એ મહત્તમ સંખ્યા \(\leq t\) છે.તો વિધેય \(f(x)=[a+13 \sin x], x \in(0, \pi)\) જ્યા વિકલનીય ન હોય તેવા બિંદુની સંખ્યા \(........\) છે.

  1. A \(24\)
  2. B \(23\)
  3. C \(22\)
  4. D \(25\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(25\)

Step-by-step Solution

Detailed explanation

\(f(x)=[a+13 \sin x], x \in(0, \pi)\) For \([n \sin x ]\); Total number of non differentiable points are \(=2 n-1\) for \(x \in(0, \pi)\) So number of non differentiable points for \([13 \sin x] \Rightarrow 25\) Points
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app