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JEE Mains · Maths · STD 11 - 4.2 Quadratic equations and inequations

વાસ્તવિક સંખ્યા \((a, b)\) ની જોડની સંખ્યા મેળવો કે જ્યારે \(\alpha\) એ સમીકરણ \(x^{2}+a x+b=0 \) નું બીજ હોય ત્યારે બીજું બીજ \( \alpha^{2}-2\)  થાય.

  1. A \(6\)
  2. B \(2\)
  3. C \(4\)
  4. D \(8\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(6\)

Step-by-step Solution

Detailed explanation

Consider the equation \(x^{2}+a x+b=0\) If has two roots (not necessarily real \(\alpha \, \& \beta\) ) Either \(\alpha=\beta\) or \(\alpha \neq \beta\) Case \((1)\) If \(\alpha=\beta\), then it is repeated root. Given that \(\alpha^{2}-2\) is also a root So,…
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