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JEE Mains · Maths · STD 11 - 4.1 complex nubers

જો \(z\) એ અસમતા \(\exp \left(\frac{(|z|+3)(|z|-1)}{|| z|+1|} \log _{ e } 2\right) \geq \log _{\sqrt{2}}|5 \sqrt{7}+9 i |\) \(i=\sqrt{-1},\)નું સમાધાન કરતી સંકર સંખ્યા હોય, તો \(|z|\) નું લઘુત્તમ મૂલ્ય ...... થાય.

  1. A \(3\)
  2. B \(\sqrt{5}\)
  3. C \(2\)
  4. D \(8\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(3\)

Step-by-step Solution

Detailed explanation

\(\exp \left(\frac{(|z|+3)(|z|-1)}{|| z|+1|} \ell\right.\) n \(\left.2\right) \geq \log _{\sqrt{2}}|5 \sqrt{7}+9 i|\) \(\Rightarrow \quad 2^{\frac{(|z|+3)(|z|-1)}{(|z|+1)} \geq \log _{\sqrt{2}}(16)}\) \(\Rightarrow \quad 2^{\frac{(|z|+3)(|z|-1)}{(|z|+1)} \geq 2^{3}}\)…
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