ExamBro
ExamBro
enEnglishguગુજરાતી
JEE Mains · Maths · STD 11 - 4.2 Quadratic equations and inequations

જો \(\alpha \) અને \(\beta \) સમીકરણ \(x^2 + px + \frac {3p}{4} = 0\) ના ઉકેલો હોય કે જેથી  \(\left| {\alpha  - \beta } \right| = \sqrt {10} ,\) તો \(p\) ની કિમત મેળવો.

  1. A \(\{2,\,-5\}\)
  2. B \(\{-3,\,2\}\)
  3. C \(\{-2,\,5\}\)
  4. D \(\{3,\,-5\}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\{-2,\,5\}\)

Step-by-step Solution

Detailed explanation

Given quadratic eqn. is \(x^{2}+p x+\frac{3 p}{4}=0\) So, \(\alpha+\beta=-p, \alpha \beta=\frac{3 p}{4}\) Now, given \(|\alpha-\beta|=\sqrt{10}\) \(\Rightarrow \alpha-\beta=\pm \sqrt{10}\) \(\Rightarrow(\alpha-\beta)^{2}=10\)…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app