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JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola

ધારો કે \(\lambda x-2 y=\mu\) એ અતિવલય \(a^{2} x^{2}-y^{2}=b^{2}\) નો સ્પર્શક છે. તો \(\left(\frac{\lambda}{a}\right)^{2}-\left(\frac{\mu}{b}\right)^{2}\) = ......

  1. A \(-2\)
  2. B \(-4\)
  3. C \(2\)
  4. D \(4\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(4\)

Step-by-step Solution

Detailed explanation

\(\lambda x -2 y =\mu\) is a tangent to the curve \(a^{2} x^{2}-y^{2}=b^{2}\) then \(a ^{2} x ^{2}-\left(\frac{\lambda x -\mu}{2}\right)^{2}= b ^{2}\) \(\left(4 a ^{2}-\lambda^{2}\right) x ^{2}+2 \lambda \mu x -\mu^{2}-4 b ^{2}=0\) Disc. \(=0\)…
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