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JEE Mains · Maths · STD 12 - 11. three dimension geometry

ધારો કે \(\lambda\) પૂર્ણાંક છે. જે રેખાઓ \(x -\lambda=2 y -1=-2 z\) અને \(x = y +2 \lambda= z -\lambda\) વચ્ચેનું લઘુત્તમ અંતર \(\frac{\sqrt{7}}{2 \sqrt{2}},\) હોય, તો \(|\lambda|\) નું મૂલ્ય ..... છે.

  1. A \(8\)
  2. B \(4\)
  3. C \(5\)
  4. D \(1\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(1\)

Step-by-step Solution

Detailed explanation

\(\frac{x-\lambda}{1}=\frac{y-\frac{1}{2}}{\frac{1}{2}}=\frac{z-0}{-\frac{1}{2}}\) \(\frac{x-0}{1}=\frac{y+2 \lambda}{1}=\frac{z-\lambda}{1}\) Shortest distance \(=\frac{\left( a _{2}- a _{1}\right) \cdot\left( b _{1} \times b _{2}\right)}{\left| b _{1} \times b _{2}\right|}\)…
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