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JEE Mains · Maths · STD 12 - 8. Application and integration

જો પરવલયો \(P _1: 2 y=5 x^2\) તથા \(P _2: x^2-y+6=0\) વચ્યે ઘેરાયેલ પ્રદેશનું ક્ષેત્રફળ એ \(P _1\) તથા \(y=\alpha x, \alpha > 0\) વચ્યે ઘેરાયેલ પ્રદેશના ક્ષેત્રફળ જેટલું હોય, તો \(\alpha^3=...........\)

  1. A \(559\)
  2. B \(600\)
  3. C \(601\)
  4. D \(602\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(600\)

Step-by-step Solution

Detailed explanation

Abscissa of point of intersection of \(2 y =5 x ^2\) and \(y=x^2+6\) is \(\pm 2\) \(\text { Area }=2 \int \limits_0^2\left(x^2+6-\frac{5 x^2}{2}\right) d x=\int \limits_0^{\frac{2 \alpha}{5}}\left(\alpha x-\frac{5 x^2}{2}\right) d x\)…
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