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JEE Mains · Maths · STD 12 - 9. differential equations

ધારો કે \(f(x)\) એક વાસ્તવિક વિકલનીય વિધેય છે કે જેથી \(f(0)=1\) અને બધા જ \(x, y \in \mathbf{R}\) માટે \(f(x+y)=f(x) f^{\prime}(y)+f^{\prime}(x) f(y)\). તો \(\sum_{\mathrm{n}=1}^{100} \log _{\mathrm{e}} f(\mathrm{n})\) = ___ છે.

  1. A \(2525\)
  2. B \(5220\)
  3. C \(2384\)
  4. D \(2406\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(2525\)

Step-by-step Solution

Detailed explanation

\(\because f(x+y)=f(x) \cdot f(y)+f(x) \cdot f(y), \forall x, y \in R\) ....(i) And \(f(0)=1\) ....(ii) Now replace \(x\) by zero and \(y\) by zero we get…
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