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JEE Mains · Maths · STD 11 - 8. sequence and series

જો \(\frac{1}{1^4}+\frac{1}{2^4}+\frac{1}{3^4}+\ldots . . \infty=\frac{\pi^4}{90},\)
\(\frac{1}{1^4}+\frac{1}{3^4}+\frac{1}{5^4}+\ldots . . \infty=\alpha,\)
\(\frac{1}{2^4}+\frac{1}{4^4}+\frac{1}{6^4}+\ldots . \infty=\beta,\)
તો \(\frac{\alpha}{\beta}\) = __________

  1. A 23
  2. B 18
  3. C 15
  4. D 14
Verified Solution

Answer & Solution

Correct Answer

(C) 15

Step-by-step Solution

Detailed explanation

If \(\frac{1}{1^4}+\frac{1}{2^4}+\frac{1}{3^4}+\ldots . . \infty=\frac{\pi^4}{90}....(i)\) \(\begin{aligned} & \beta=\frac{1}{2^4}+\frac{1}{4^4}+\frac{1}{6^4}+\ldots, \\ & =\frac{1}{16}\left[\frac{1}{1^4}+\frac{1}{2^4}+\frac{1}{3^4}+\ldots . .\right],\end{aligned}\)…
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