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JEE Mains · Maths · STD 11 - 12. limits

ધારો કે \(f(x)=\left\{\begin{array}{ll}\frac{ a x^2+2 a x+3}{4 x^2+4 x-3} & , x \neq-\frac{3}{2}, \frac{1}{2} \\ b & , x=-\frac{3}{2}, \frac{1}{2}\end{array}\right.\) એ \(x=-\frac{3}{2}\) પર સતત છે. જો \(f \circ f(x)=\frac{7}{5}\) હોય, તો x = ___ .

  1. A 2
  2. B 1
  3. C 0
  4. D 1.4
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Answer & Solution

Correct Answer

(B) 1

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Detailed explanation

\(f(x)=\left\{\begin{array}{cc}\frac{a^2+2 a x+3}{(2 x-1)(2 x+3)} & ; x \neq \frac{-3}{2}, \frac{1}{2} \\ b & ; x=\frac{-3}{2}, \frac{1}{2}\end{array}\right.\) for continuous at \(x=\frac{-3}{2}\) \(LHL=RHL\)…
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