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JEE Mains · Maths · STD 11 - 12. limits

ધારો કે \( f:R\rightarrow(0,\infty) \) એ એક દ્વિવિધ વિકલનીય વિધેય છે જેથી \( f(3)=18, \) \( f^{\prime}(3)=0 \) અને \( f^{\prime\prime}(3)=4 \). તો \( \lim_{x\rightarrow1}(\log_{e}(\frac{f(x+2)}{f(3)})^{\frac{18}{(x-1)^{2}}}) \) = ........... છે.

  1. A 1
  2. B 9
  3. C 2
  4. D 18
Verified Solution

Answer & Solution

Correct Answer

(C) 2

Step-by-step Solution

Detailed explanation

Let \( T=\lim_{x\rightarrow1}(\frac{f(x+2)}{f(3)})^{\frac{18}{(x-1)^{2}}} \) ; \( 1^{\infty} \) form \( \Rightarrow T=e^{\lim_{x\rightarrow1}\frac{18}{(x-1)^{2}}(\frac{f(x+2)-f(3)}{f(3)})} \)…
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