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JEE Mains · Maths · STD 12 - 7.2 definite integral

ધારો કે \(f:\left[-\frac{\pi}{2}, \frac{\pi}{2}\right] \rightarrow R\) એવો વિકલનીય વિધેય છે કે જેથી \(f(0)=\frac{1}{2}\) થાય. જો \(\lim _{x \rightarrow 0} \frac{x \int_0^x f(\mathrm{t}) \mathrm{dt}}{\mathrm{e}^{x^2}-1}=\alpha\) હોય, તો \(8 \alpha^2 =\) ...........

  1. A \(16\)
  2. B \(2\)
  3. C \(1\)
  4. D \(4\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2\)

Step-by-step Solution

Detailed explanation

\( \lim _{x \rightarrow 0} \frac{x \int_0^x f(t) d t}{\left(\frac{e^{x^2}-1}{x^2}\right) \times x^2}\) \( \lim _{x \rightarrow 0} \frac{\int_0^x f(t) d t}{x} \quad\left(\lim _{x \rightarrow 0} \frac{e^{x^2}-1}{x^2}=1\right)\)…
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