JEE Mains · Maths · STD 12 - 7.2 definite integral
Let \(f:\left[-\frac{\pi}{2}, \frac{\pi}{2}\right] \rightarrow R\) be a differentiable function such that \(f(0)=\frac{1}{2}\), If the \(\lim _{x \rightarrow 0} \frac{x \int_0^x f(t) d t}{e^{x^2}-1}=\alpha\), then \(8 \alpha^2\) is equal to :
- A \(16\)
- B \(2\)
- C \(1\)
- D \(4\)
Answer & Solution
Correct Answer
(B) \(2\)
Step-by-step Solution
Detailed explanation
\( \lim _{x \rightarrow 0} \frac{x \int_0^x f(t) d t}{\left(\frac{e^{x^2}-1}{x^2}\right) \times x^2}\) \( \lim _{x \rightarrow 0} \frac{\int_0^x f(t) d t}{x} \quad\left(\lim _{x \rightarrow 0} \frac{e^{x^2}-1}{x^2}=1\right)\)…
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