ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Maths · STD 11 - 9. straight line

ધારો કે \(\mathrm{ABC}\) એ એક સમદ્વિબાજુ ત્રિકોણ છે, જેમાં \(\mathrm{A}\) એ \((-1,0)\) આગળ છે, \(\angle \mathrm{A}=\frac{2 \pi}{3}, \mathrm{AB}=\mathrm{AC}\) અને \(\mathrm{B}\) એ ધન \(x\)-અક્ષ પર આવેલી છે. જો \(\mathrm{BC}=4 \sqrt{3}\) અને રેખા \(\mathrm{BC}\) એ, રેખા \(y=x+3\) ને \((\alpha, \beta)\) આગળ છેદે તો \(\frac{\beta^4}{\alpha^2}\) = ...........

  1. A \(85\)
  2. B \(36\)
  3. C \(45\)
  4. D \(75\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(36\)

Step-by-step Solution

Detailed explanation

\(\frac{\mathrm{c}}{\sin 30^{\circ}}=\frac{4 \sqrt{3}}{\sin 120^{\circ}}\) [By sine rule] \(2 c=8 \Rightarrow c=4\) \( \mathrm{AB}=|(\mathrm{b}+1)|=4 \) \( \mathrm{~b}=3, \mathrm{~m}_{\mathrm{AB}}=0 \) \( \mathrm{~m}_{\mathrm{BC}}=\frac{-1}{\sqrt{3}} \)…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app