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JEE Mains · Maths · STD 12 - 9. differential equations

બિંદૂ \((0,1)\) માંથી પસાર થતો, વિકલ સમીકરણ \(2 y \frac{\mathrm{d} y}{\mathrm{~d} x}+3=5 \frac{\mathrm{d} y}{\mathrm{~d} x}\) નો ઉકેલ વક્ર એક શાંકવ છે, જેનું શિરોબિંદૂ ............. રેખા પર આવેલું છે.

  1. A  \(2 x+3 y=9\)
  2. B \(2 x+3 y=-9\)
  3. C \(2 x+3 y=-6\)
  4. D \(2 x+3 y=6\)
Verified Solution

Answer & Solution

Correct Answer

(A)  \(2 x+3 y=9\)

Step-by-step Solution

Detailed explanation

\( (2 y-5) \frac{d y}{d x}=-3 \) \( (2 y-5) d y=-3 d x \) \( 2 \cdot \frac{y^2}{2}-5 y=-3 x+\lambda\) \(\because\) Curve passes through \((0,1)\) \(\Rightarrow \lambda=-4\) \(\because\) Curve will be \(\left(y-\frac{5}{2}\right)^2=-3\left(x-\frac{3}{4}\right)\) \(\therefore\)…
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