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JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant

અહી  \(P\) એ ચોરસ શ્રેણિક છે કે જેથી  \(P ^2= I - P\) થાય.  \(\alpha, \beta, \gamma, \delta \in N\) માટે જો \(P ^\alpha+ P ^\beta=\gamma I -29 P\) અને \(P ^\alpha- P ^\beta=\) \(\delta I-13 P\) હોય તો \(\alpha+\beta+\gamma-\delta\) ની કિમંત મેળવો.

  1. A \(18\)
  2. B \(40\)
  3. C \(24\)
  4. D \(22\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(24\)

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Detailed explanation

\(P ^2= I - P\) \(P ^\alpha+ P ^\beta=\gamma I -29 P , P ^\alpha- P ^\beta=\delta I -13 P\) \(P ^4=( I - P )^2= I -2 P + P ^2=2 I -3 P\) \(P ^6=(2 I -3 P )( I - P )=5 I -8 P\) \(P ^8=(2 I -3 P )^2=4 I -12 P +9( I - P )=13 I -21 P\) \(P ^8+ P ^6=18 I -29 P\)…
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