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JEE Mains · Maths · STD 12 - 6. Application of derivatives

અહી \(f(x)=\left\{\begin{array}{cc}x^{3}-x^{2}+10 x-7, & x \leq 1 \\ -2 x+\log _{2}\left(b^{2}-4\right), & x>1\end{array}\right.\)  હોય તો \(b\) ની બધીજ કિમંતો નો ગણ મેળવો કે જેથી \(f(x)\) ની મહતમ કિમંત \(x=1\) આગળ થાય.

  1. A \((-6,-2)\)
  2. B \((2,6)\)
  3. C \([-6,-2) \cup(2,6]\)
  4. D \([-\sqrt{6},-2) \cup(2, \sqrt{6}]\)
Verified Solution

Answer & Solution

Correct Answer

(C) \([-6,-2) \cup(2,6]\)

Step-by-step Solution

Detailed explanation

\(f(1)=3\) For \(x <1, f ^{\prime}( x )=3 x ^{2}-2 x +10>0\) \(\Rightarrow f ( x )\) is increasing For \(x >1, f ^{\prime}( x )<0\) function is decreasing. \(\lim _{x \rightarrow 1^{+}} f(x)=-2+\log _{2}\left(b^{2}-4\right)\) For maximum value at \(x=1\)…
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