ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Maths · STD 12 - 13. probability

\(a \in[-5,30]\) માંથી પૂર્ણાંકની પસંદગીની સંભાવના મેળવો કે જેથી દરેક \(x \in R\) માટે \(x^{2}+2(a+4) x-5 a+64>0\) મેળવો.

  1. A \(\frac{1}{4}\)
  2. B \(\frac{7}{36}\)
  3. C \(\frac{2}{9}\)
  4. D \(\frac{1}{6}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{2}{9}\)

Step-by-step Solution

Detailed explanation

\(\mathrm{D}<0\) \(\Rightarrow 4(a+4)^{2}-4(-5 a+64)<0\) \(\Rightarrow a^{2}+16+8 a+5 a-64<0\) \(\Rightarrow a^{2}+13 a-48<0\) \(\Rightarrow(a+16)(a-3)<0\) \(\Rightarrow a \in(-16,3)\) \(\therefore\) Possible a : \(\{-5,-4, \ldots, 2\}\) \(\therefore\) Required probability…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app