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JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola

ઉપવલય \(\frac{\mathrm{x}^2}{\mathrm{a}^2}+\frac{\mathrm{y}^2}{\mathrm{~b}^2}=1, \mathrm{a}>\mathrm{b}\) ની નાભિ અને નાભિલંબની લંબાઈ અનુક્રમે \(( \pm 5,0)\) અને \(\sqrt{50}\) છે, તો અતિવલય \(\frac{x^2}{a^2}-\frac{y^2}{a^2 b^2}=1\) ની ઉત્કેન્દ્રતાનો વર્ગ ........... છે.

  1. A \(40\)
  2. B \(48\)
  3. C \(51\)
  4. D \(50\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(51\)

Step-by-step Solution

Detailed explanation

\(\text { focii } \equiv( \pm 5,0) ; \frac{2 b^2}{a}=\sqrt{50} \) \(ae=5 \quad b^2=\frac{5 \sqrt{2} a}{2} \) \(b^2=a^2\left(1-e^2\right)=\frac{5 \sqrt{2} a}{2}\) \( \Rightarrow \mathrm{a}\left(1-\mathrm{e}^2\right)=\frac{5 \sqrt{2}}{2}\)…
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