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JEE Mains · Maths · STD 11 - 7. binomial theoram

\((1+x)^{10}\) ના દ્વિપદી વિસ્તરણમાં \(x^{10-r}\) નો સણગુણક જો \(a_r\) હોય., તો \(\sum \limits_{r=1}^{10} r^3\left(\frac{a_r}{a_{r-1}}\right)^2=...............\)

  1. A \(4895\)
  2. B \(1210\)
  3. C \(5445\)
  4. D \(3025\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(1210\)

Step-by-step Solution

Detailed explanation

\(a _{ r }={ }^{10} C _{10- r }={ }^{10} C _{ r }\) \(\Rightarrow \sum \limits_{ r =1}^{10} r ^3\left(\frac{{ }^{10} C _{ r }}{{ }^{10} C _{ r -1}}\right)^2=\sum \limits_{ r =1}^{10} r ^3\left(\frac{11- r }{ r }\right)^2=\sum \limits_{ r =1}^{10} r (11- r )^2\)…
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