ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Chemistry · STD 12 - 2. Electrochemistry

\(Pd ^{2+}+4 Cl ^{-} \rightleftharpoons PdCl _4^{2-}\) પ્રક્રિયા માટે સંતુલન અચળાંકનો લધુગણક \(...........\) (નજીકનો પૂર્ણાંક) આપેલ \(: \frac{2.303 RT }{ F }=0.06 V\) \(Pd _{( aq )}^{2+}+2 e ^{-} \rightleftharpoons Pd ( s ) \quad E ^{\circ}=0.83\,V\) \(PdCl _4^{2-}( aq )+2 e ^{-} \rightleftharpoons Pd ( s )+4 Cl ^{-}( aq )\) \(E ^{\circ}=0.65\,V\)

  1. A \(3\)
  2. B \(4\)
  3. C \(12\)
  4. D \(6\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(6\)

Step-by-step Solution

Detailed explanation

\(\Delta G ^{\circ}=- RT \ell nK\) \(- nFE\) \(\text { cell }=- RT \times 2.303\left(\log _{10} K \right)\) \(\frac{ E _{ Cell }^{ o }}{0.06} \times n =\log K\) \(Pd ^{+2}( aq .)+ 2 e ^{-} \rightleftharpoons Pd ( s ), E _{\text {cat,red }}^{ o }=0.83\)…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app