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JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)

બ્યૂટિરિક એસિડ \(\left( C _{3} H _{7} COOH \right)\) માટે \(K _{ a }\) એ \(2 \times 10^{-5}\) છે. તો બ્યૂટિરિક એસિડના \(0.2 \,M\) દ્રાવણની \(pH\) .......... \(\times 10^{-1}\) છે. (નાજુકના પૂર્ણાકમાં) [આપેલ \(\log 2=0.30]\)

  1. A \(26\)
  2. B \(25\)
  3. C \(27\)
  4. D \(29\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(27\)

Step-by-step Solution

Detailed explanation

\(K _{ a }\) of Butyric acid \(\Rightarrow 2 \times 10^{-5} PKa =4.7\) \(pH\) of \(0.2\,M\) solution \(pH =\frac{1}{2} pK _{ a }-\frac{1}{2} \log C\) \(=\frac{1}{2}(4 \cdot 7) \frac{1}{2} \log (0.2)\) \(=2.35+0.35=2.7\) \(pH =27 \times 10^{-1}\)
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