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JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)

\(5.0\, {~mL}\) \(0.0504\, {M} \,{NH}_{4} {Cl}\) અને \(2\, {~mL}\)  \(0.0210 \,{M}\, {NH}_{3},\) \(0.0210 \,{M}\, {NH}_{3}\) દ્રાવણમાં \({x} \,\times 10^{-6}\, {M}\) મિશ્રણમાં \(OH^-\)ની સાંદ્રતા છે. \({x}\)નું મૂલ્ય \(.....\) છે. (નજીકના પૂર્ણાંકમાં) \(\left[\right.\) આપેલ છે: \({K}_{m}=1 \times 10^{-14}\) અને \(\left.{K}_{{b}}=1.8 \times 10^{-5}\right]\)

  1. A \(3\)
  2. B \(4\)
  3. C \(5\)
  4. D \(6\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(3\)

Step-by-step Solution

Detailed explanation

\(\left[{NH}_{4}^{+}\right]=0.0504 \,\&\,\left[{NH}_{3}\right]=0.0210\) So \({K}_{b}=\frac{\left[{NH}_{4}^{+}\right]\left[{HO}^{-}\right]}{\left[{NH}_{3}\right]}\)…
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