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JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties

\(27^{\circ}\,C\) અને \(1\) વાતા. દબાાણ પર, \(SO _2( g )+\frac{1}{2} O _2( g )= SO _3( g )\) પ્રક્રિયા માટે,\(K _{ p }=2 \times 10^{12} છ\). આ જ પ્રક્રિયા માટે \(K _{ c }.......\times 10^{13}\) છે. (આપેલ : \(R =0.083\,L\,bar\,K ^{-1}\,mol ^{-1}\) )

  1. A \(62240\)
  2. B \(62258\)
  3. C \(62240\)
  4. D \(62250\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(62250\)

Step-by-step Solution

Detailed explanation

\(\pi= CRT\) \(\frac{400\,Pa }{10^5}=\frac{\frac{2.5\,g }{ M _o}}{250 / 1000\,L } \times 0.83 \frac{ L - bar }{ K \cdot mol } \times 300\,K\) \(M _0=62250\)
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