એક નાના ગજિયા ચુંબકને તેની અક્ષ 0.5 Tના નિયમિત બાહ્ય ચુંબકીય ક્ષેત્ર સાથે 30° કોણ બનાવે તે રીતે મૂકતાં \(4.5 \times 10^{-2} J\) જેટલું ટોર્ક અનુભવે છે. ચુંબકની મેગ્નેટિક મોમેન્ટનું મૂલ્ય હશે.

A \(3.6 \times 10^2 J T ^{-1}\)
B \(36 \times 10^{-2} J T ^{-1}\)
C \(1.8 \times 10^2 J T ^{-1}\)
D \(18 \times 10^{-2} J T ^{-1}\)

Verified Solution

Answer & Solution

Correct Answer

(D) \(18 \times 10^{-2} J T ^{-1}\)

Step-by-step Solution

Detailed explanation

\(\begin{array}{l}\tau=m B \sin \theta \\ 4.5 \times 10^{-2}=m \times 0.5 \times \sin 30^{\circ} \\ 4.5 \times 10^{-2}=m \times \frac{1}{2} \times \frac{1}{2} \\ m=4.5 \times 10^{-2} \times 2 \times 2 \\ m=18 \times 10^{-2} J T ^{-1}\end{array}\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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