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GUJCET · Maths · Inverse Trigonometric Functions

જો \(2 \sin ^{-1} x=\sin ^{-1}\left(2 x \sqrt{1-x^2}\right)\) તો, \(x \in\) _________.

  1. A \(\left\lfloor\frac{1}{\sqrt{2}}, 1\right\rfloor\)
  2. B \([0,1]\)
  3. C \(\left[\frac{-1}{\sqrt{2}}, \frac{1}{\sqrt{2}}\right]\)
  4. D \(\left[\frac{-1}{\sqrt{2}}, 1\right]\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\left[\frac{-1}{\sqrt{2}}, \frac{1}{\sqrt{2}}\right]\)

Step-by-step Solution

Detailed explanation

ધારો કે \(x = \sin\theta\). સમીકરણ \(2\theta = \sin^{-1}(\sin 2\theta)\) ત્યારે જ સાચું છે જો \(-\frac{\pi}{2} \le 2\theta \le \frac{\pi}{2}\).
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