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GUJCET · Maths · Determinants

\(\triangle \mathrm{ABC}\) માટે, \(\left|\begin{array}{ccc}0 & \sin \mathrm{~A} & \tan \mathrm{~B} \\ -\sin (\mathrm{B}+\mathrm{C}) & 0 & \cos \mathrm{C} \\ \tan (\mathrm{A}+\mathrm{C}) & -\cos \mathrm{C} & 0\end{array}\right|\) = _________

  1. A 1
  2. B \(-1\)
  3. C \(0\)
  4. D \(\sin \mathrm{A} \cos \mathrm{C}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(0\)

Step-by-step Solution

Detailed explanation

\( -\sin ( B + C ) = -\sin ( \pi - A ) = -\sin A \) \( \tan ( A + C ) = \tan ( \pi - B ) = -\tan B \)
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