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GUJCET · Maths · Determinants
For \(\triangle ABC ,\left|\begin{array}{ccc}0 & \sin A & \tan B \\ -\sin ( B + C ) & 0 & \cos C \\ \tan ( A + C ) & -\cos C & 0\end{array}\right|=\) ____________ .
- A 1
- B -1
- C 0
- D \(\sin A \cos C\)
Answer & Solution
Correct Answer
(C) 0
Step-by-step Solution
Detailed explanation
\( -\sin ( B + C ) = -\sin ( \pi - A ) = -\sin A \) \( \tan ( A + C ) = \tan ( \pi - B ) = -\tan B \)
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