WBJEE · Physics · Capacitance
Three capacitors \(3 \mu \mathrm{F}, 6 \mu \mathrm{F}\) and \(6 \mu \mathrm{F}\) are connected in aeries to a source of \(120 \mathrm{V}\). The potential difference, in volt, across the \(3 \mu \mathrm{F}\) capacitor will be
- A 24
- B 30
- C 40
- D 60
Answer & Solution
Correct Answer
(D) 60
Step-by-step Solution
Detailed explanation
The combination of three charges in series \[ \begin{array}{l} \frac{1}{C}=\frac{1}{C_{1}}+\frac{1}{C_{2}}+\frac{1}{C_{3}} \\ \frac{1}{C}=\frac{1}{3}+\frac{1}{6}+\frac{1}{6} \Rightarrow C=\frac{6}{4}=1.5 \mu \mathrm{F} \end{array} \] The charge of this circuit…
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