WBJEE · Maths · Basic of Mathematics
In a right-angled triangle, the sides are \(a, b\) and \(c\), with \(c\) as hypotenuse, and \(c-b \neq 1, c+b \neq 1\). Then the value of \(\left(\log _{c+b} a+\log _{c-b} a\right) /\left(2 \log _{c+b} a \times \log _{c-b} a\right)\) will be
- A 2
- B -1
- C \(\frac{1}{2}\)
- D 1
Answer & Solution
Correct Answer
(D) 1
Step-by-step Solution
Detailed explanation
Hints : \(c^2=a^2+b^2\) \(\Rightarrow \mathrm{c}^2-\mathrm{b}^2=\mathrm{a}^2\)…
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