WBJEE · Physics · Gravitation
Average distance of the Earth from the Sun is \(L_{1}\) : If one year of the Earth \(=D\) days, one year of another planet whose average distance from the Sun is \(L_{2}\) will be
- A \(D\left(\frac{L_{2}}{L_{1}}\right)^{\frac{1}{2}}\) days
- B \(D\left(\frac{L_{2}}{L_{1}}\right)^{\frac{3}{2}}\) days
- C \(D\left(\frac{L_{2}}{L_{1}}\right)^{\frac{2}{3}}\) days
- D \(D\left(\frac{L_{2}}{L_{1}}\right)\) days
Answer & Solution
Correct Answer
(B) \(D\left(\frac{L_{2}}{L_{1}}\right)^{\frac{3}{2}}\) days
Step-by-step Solution
Detailed explanation
By Keplar's law, \[ \begin{array}{l} T^{2} \propto R^{3} \\ T=D\left(\frac{L_{2}}{L_{1}}\right)^{3 / 2} \end{array} \]
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