WBJEE · Maths · Application of Derivatives
Maximum value of the function \(f(x)=\frac{x}{8}+\frac{2}{x}\) on the interval [1,6] is
- A 1
- B \(\frac{9}{8}\)
- C \(\frac{13}{12}\)
- D \(\frac{17}{8}\)
Answer & Solution
Correct Answer
(D) \(\frac{17}{8}\)
Step-by-step Solution
Detailed explanation
\(f(x)=\frac{x}{8}+\frac{2}{x}\) \(\therefore \quad f^{\prime}(x)=\frac{1}{8}-\frac{2}{x^{2}}=\frac{x^{2}-16}{8 x^{2}}\) For maximum or minimum \(f^{\prime}(x)\) must be vanish.…
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