WBJEE · Physics · Center of Mass Momentum and Collision
A small steel ball bounces on a steel plate held horizontally. On each bounce the speed of the ball arriving at the plate is reduced by a factor
e (coefficient of restitution) in the rebound, so that \(V_{upward}=eV_{downward}\)
If the ball is initially dropped from a height of \(0.4 \mathrm{m}\) above the plate and if 10 seconds later the bouncing ceases, the value of \(e\) is
- A \(\sqrt{\frac{2}{7}}\)
- B \(\frac{3}{4}\)
- C \(\frac{13}{18}\)
- D \(\frac{17}{18}\)
Answer & Solution
Correct Answer
(D) \(\frac{17}{18}\)
Step-by-step Solution
Detailed explanation
Given, steel ball bounces on a steel ple held horizontally, so \[ V_{\text {upward }}=e V_{\text {downward }} \] According to the relation, \(h_{n}=e^{2 n} h\)…
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