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TS EAMCET · Physics · Laws of Motion

A particle moves over a xy plane with a constant acceleration a=4.0 m s-2i^+4.0 m s-2j^. At the time t=0, the velocity is 4.0 m s-2i^. The speed of the particle when it is displaced by 6.0 m parallel to the x-axis is,

  1. A 45 m s-1
  2. B 60 m s-1
  3. C 310 m s-1
  4. D 20 m s-1
Verified Solution

Answer & Solution

Correct Answer

(A) 45 m s-1

Step-by-step Solution

Detailed explanation

According to the second equation, of motion, in terms of initial velocity and uniform acceleration, s=ut+12at2, the displacement is given, s=6 m, 6=4t+124t2⇒2t2+2t-62=0⇒t2+2t-3=0 Now find the root of the above equation, ⇒t=-2±4+122=1 s then the…
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