TS EAMCET · Physics · Mechanical Properties of Solids
A slab of side \(50 \mathrm{~cm}\) and thickness \(10 \mathrm{~cm}\) is subjected to a shearing force of \(10^5 \mathrm{~N}\) on its narrow edge. If the lower edge is riveted to the floor and upper edge is displaced by \(0.2 \mathrm{~mm}\), then shear modulus of the material of the slab is
- A 6 GPa
- B 5 GPa
- C 4 GPa
- D 4.5 GPa
Answer & Solution
Correct Answer
(B) 5 GPa
Step-by-step Solution
Detailed explanation
The given situation is shown in the following figure. Shear strain \(=\frac{x}{l}=\frac{0.2 \mathrm{~mm}}{50 \mathrm{~cm}}=\frac{0.2 \times 10^{-3}}{50 \times 10^{-2}}\) Shear stress…
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