TS EAMCET · Physics · Electromagnetic Induction
Consider a metal ball of radius \(r\) moving at a constant velocity \(v\) in a wiform magnetic field of induction \(\bar{B}\). Assuming that the direction of velocity forms an angle \(\alpha\) with the direction of \(\bar{B}\), the maximum potential difference between points on the ball is
- A \(r|\bar{B}||\bar{v}| \sin \alpha\)
- B \(|\bar{B}||\bar{v}| \sin \alpha\)
- C \(2 r|\bar{B}||\bar{v}| \sin \alpha\)
- D \(2 r|\bar{B}||\bar{v}| \cos \alpha\)
Answer & Solution
Correct Answer
(C) \(2 r|\bar{B}||\bar{v}| \sin \alpha\)
Step-by-step Solution
Detailed explanation
Given, Radius of metal ball \(=r\) Velocity \(=v\) Angle between direction of velocity and magnetic field \((B)=\alpha\) We know that, \[ e=B l v \sin \alpha \] Here, \(l=2 r\) \[ e=2 r|B \|| v \mid \sin \alpha \]
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