TS EAMCET · Physics · Thermodynamics
A diesel engine has a compression ratio of \(20: 1\). If the initial pressure is \(1 \times 10^5 \mathrm{~Pa}\) and the initial volume of the cylinder is \(1 \times 10^{-3} \mathrm{~m}^3\), then how much work does the gas do during the compression? (Assume the process as adiabatic) \[ \left(C_V=20.8 \mathrm{~J} / \mathrm{mol} \mathrm{K}, \psi_{\text {air }}=1.4,(20)^{1.4}=66.3\right) \]
- A \(-880 \mathrm{~J}\)
- B \(-579 \mathrm{~J}\)
- C \(220 \mathrm{~J}\)
- D \(485 \mathrm{~J}\)
Answer & Solution
Correct Answer
(B) \(-579 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
Compression ratio \(=\frac{\text { Initial volume }}{\text { Final volume }}=\frac{20}{1}\) \[ \begin{aligned} \frac{V_1}{V_2} & =\frac{20}{1} \\ V_2 & =\frac{V_1}{20}=\frac{10^{-3}}{20} \mathrm{~m}^3 \end{aligned} \] In adiabatic process,…
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