TS EAMCET · Physics · Kinetic Theory of Gases
\(\mathrm{N}\) molecules each of mass \(\mathrm{m}\) of gas \(\mathrm{A}\) and \(2 \mathrm{~N}\) molecules each of mass \(2 \mathrm{~m}\) of gas \(\mathrm{B}\) are contained in a vessel which is maintained at temperature \(T\). The mean square velocity of the molecules of gas B is denoted by \(V_2^2\) and the mean square of the \(\mathrm{X}\)-component velocity of the molecules of gas \(A\) is denoted by \(V_1^2\), then \(\frac{V_1}{V_2}\) is
- A \(2\)
- B \(1\)
- C \(\frac{2}{3}\)
- D \(\sqrt{\frac{2}{3}}\)
Answer & Solution
Correct Answer
(D) \(\sqrt{\frac{2}{3}}\)
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Detailed explanation
The mean square velocity of gas molecule is given by…
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