TS EAMCET · Physics · Current Electricity
In the circuit shown, the heat produced in \(5 \Omega\) resistance due to current through is \(50 \mathrm{~J} / \mathrm{s}\). Then, the heat generated per second in \(2 \Omega\) resistance is
- A \(5 \mathrm{~J} / \mathrm{s}\)
- B \(4 \mathrm{~J} / \mathrm{s}\)
- C \(9 \mathrm{~J} / \mathrm{s}\)
- D \(10 \mathrm{~J} / \mathrm{s}\)
Answer & Solution
Correct Answer
(A) \(5 \mathrm{~J} / \mathrm{s}\)
Step-by-step Solution
Detailed explanation
The given \(P=50 \mathrm{~J} / \mathrm{s}\) \( P=V i \Rightarrow P=i^2 R \) \( \begin{aligned} \Rightarrow i_2^2 & =\frac{P}{R}=\frac{50}{5}=10 \mathrm{Amp}^2 \\ V & \left.=i_2 R_{(5} \Omega\right) \\ & =\sqrt{10} \times 5=\sqrt{250} \mathrm{~V} \end{aligned} \) and \(2 \Omega\)…
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