TS EAMCET · Physics · Thermal Properties of Matter
The length of a metal rod is 20 cm and its area of cross-section is \(4 \mathrm{~cm}^2\). If one end of the rod is kept at a temperature of \(100^{\circ} \mathrm{C}\) and the other end is kept in ice at \(0{ }^{\circ} \mathrm{C}\), then the mass of the ice melted in 7 minutes is
(Thermal conductivity of the metal \(=90 \mathrm{Wm}^{-1} \mathrm{~K}^{-1}\) and latent heat of fusion of ice \(=336 \times 10^3 \mathrm{~J} \mathrm{~kg}^{-1}\) )
- A 20 g
- B 67.5 g
- C 22.5 g
- D 45 g
Answer & Solution
Correct Answer
(C) 22.5 g
Step-by-step Solution
Detailed explanation
\(Q = \frac{kA\Delta T t}{L}\) \(Q = \frac{90 \times (4 \times 10^{-4} \mathrm{~m}^2) \times 100 \mathrm{~K} \times (7 \times 60 \mathrm{~s})}{0.20 \mathrm{~m}}\) \(Q = \frac{90 \times 4 \times 10^{-4} \times 100 \times 420}{0.20} \mathrm{~J} = 7560 \mathrm{~J}\)…
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