TS EAMCET · Physics · Atomic Physics
A hydrogen sample is prepared in a particular excited state \(A\) of quantum number, \(n_A=3\). The ground state energy of hydrogen atom is \(-|E|\). The photons of energy \(\frac{|E|}{12}\) are absorbed in the sample which results in the excitation of some electrons to excited state \(B\) of quantum number \(n_B\), whose value is
- A 6
- B 4
- C 5
- D 7
Answer & Solution
Correct Answer
(A) 6
Step-by-step Solution
Detailed explanation
Given, energy of hydrogen atom in ground state \(=-|E|\) and \(n_A=3\) \(\therefore\) Energy of electrons in excited state, \(n_A\) \((E)_{n_A}=\frac{-|E|}{n_A^2}\) Energy of electrons in excited state, \(n_B\) \(=(E)_{n B}=\frac{-(E)}{n_B^2}\) When sample absorbs the photon of…
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