TS EAMCET · Maths · Application of Derivatives
If \(\theta\) is the angle between the curves \(x y=2\) and \(x^2+4 y=0\) and \(x^2+4 y=0\), then \(\tan \theta\) is equal to :
- A 1
- B -1
- C 2
- D 3
Answer & Solution
Correct Answer
(D) 3
Step-by-step Solution
Detailed explanation
The equation of curves are \(x y=2\) \(\ldots\) (i) and \(\quad x^2+4 y=0\) \(\ldots\) (ii) On solving Eqs. (i) and (ii), we get Point of intersection which is \((2,-1)\). From Eq. (i) \(x \frac{d y}{d x}+y=0\) \(\Rightarrow \quad \frac{d y}{d x}=-\frac{y}{x}\)…
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