TS EAMCET · Maths · Straight Lines
If the perpendicular distance between the point \((1,1)\) to the line \(3 x+4 y+c=0\) is 7 , then the possible values of \(c\) are
- A \(-35,42\)
- B 35,28
- C \(42,-28\)
- D \(28,-42\)
Answer & Solution
Correct Answer
(D) \(28,-42\)
Step-by-step Solution
Detailed explanation
We know that, distance from point \(\left(x_1, y_1\right)\) to the line \(a x+b y+c=0\) is \[ \left|\frac{a x_1+b y_1+c}{\sqrt{a^2+b^2}}\right| \] \(\therefore\) Distance from \((1,1)\) to \(3 x+4 y+c=0\) is 7…
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