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TS EAMCET · Physics · Rotational Motion

A thin uniform rod of mass 1 kg and length 1 m is hanged at one end to the ground floor. It originally stands vertically and is allowed to fall to the ground. If the rod hits the ground with angular speed ω then the correct statement is (Assume g=10 m s-2

  1. A ω=30 rad s-1
  2. B ω=20 rad s-1
  3. C ω=5 rad s-1
  4. D ω=6 rad s-1
Verified Solution

Answer & Solution

Correct Answer

(A) ω=30 rad s-1

Step-by-step Solution

Detailed explanation

By the conservation of energy, mgL2=12Iω2, the moment of inertia of rod when the axis of rotation passing through one end is, I=ML23, it means, ω=3gL, given, L=1 m, it means, ω=3×10×1=30 rad s-1
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