TS EAMCET · Maths · Circle
The equation of the circle passing through \((1,2)\) and the points of intersection of the circles \(x^2+y^2-8 x-6 y+21=0\) and \(x^2+y^2-2 x-15=0\), is
- A \(x^2+y^2+6 x-2 y+9=0\)
- B \(x^2+y^2-6 x-2 y+9=0\)
- C \(x^2+y^2-6 x-4 y+9=0\)
- D \(x^2+y^2-6 x+4 y+9=0\)
Answer & Solution
Correct Answer
(C) \(x^2+y^2-6 x-4 y+9=0\)
Step-by-step Solution
Detailed explanation
The equation of the circle passing through the points of intersection of the given circles, is \[ \begin{aligned} \left(x^2+y^2\right. & -8 x-6 y+21) \\ & +\lambda\left(x^2+y^2-2 x-15\right)=0 \end{aligned} \] If this circle passes through point \((1,2)\), then…
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