TS EAMCET · Chemistry · Classification of Elements and Periodicity in Properties

Arrange the following in the decreasing order of radius. \[ \mathrm{S}^{2-}, \mathrm{P}^{3-}, \mathrm{Cl}^{-}, \mathrm{Ca}^{2+}, \mathrm{Ar}^{+} \mathrm{K}^{+} \]

A \(\mathrm{P}^3>\mathrm{S}^2>\mathrm{Cl}>\mathrm{Ar}>\mathrm{K}^{+}>\mathrm{Ca}^{2+}\)
B \(\mathrm{Cl}>\mathrm{P}^3>\mathrm{S}^2>\mathrm{Ar}>\mathrm{K}^{+}>\mathrm{Ca}^{2+}\)
C \(\mathrm{Ar}>\mathrm{P}^3>\mathrm{S}^2>\mathrm{Cl}>\mathrm{Ca}^{2+}>\mathrm{K}^{+}\)
D \(\mathrm{K}^{+}>\mathrm{Ca}^{2+}>\mathrm{Cl}>\mathrm{S}^2>\mathrm{P}^3>\mathrm{Ar}\)

Verified Solution

Answer & Solution

Correct Answer

(A) \(\mathrm{P}^3>\mathrm{S}^2>\mathrm{Cl}>\mathrm{Ar}>\mathrm{K}^{+}>\mathrm{Ca}^{2+}\)

Step-by-step Solution

Detailed explanation

Among isoelectronic species, when negative charge present at atomic species than radii of species increase in comparison of parent atom. On the other hand positive charge at atomic species decreases the atomic radii. In other words, more be the value of negative charge and less…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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